Example:

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Any library or framework that can do it would be fine, too. Is it really that difficult to do that? In order to use a Date object in any sort of calculation, we must first retrieve the Date's internal millisecond value, which is stored as a large integer. Lets begin this tutorial by getting to the heart of it: Date.

Insults are not welcome. The subtraction operator - coerces the arguments to number, so the Date returns its time value. It might be flawed in border cases as I haven't tested it thoroughly, but it works for all the dates provided in the original question, thus I'm confident.

Days Calculator: Days Between Two Dates

As mentioned in the article, there are very few native date calculation functions in JavaScript. In fact, there are none other than to convert between local and UTC time. Left to their own devices, web developers have devised many ways of calculating date intervals, some of which are ingenious, while others are flawed or just plain wrong. I've scoured the Internet for some of the very best date interval calculation formulas so that I may present them to you today in easy-to-use static Date functions. I hope you find them useful! Adding and Subtracting from a Given Date According to the documentation, Date setters expect an interval-appropriate value. The setDays setter, for instance, expects a day from 1 to 31. In order to use a Date object in any sort of calculation, we must first retrieve the Date's internal millisecond value, which is stored as a large integer. The function to do that is Date. Once both Dates have been converted, subtracting the later one from the earlier one returns the difference in milliseconds. The desired interval can then be determined by dividing that number by the corresponding number of milliseconds. For instance, to obtain the number of days for a given number of milliseconds, we would divide by 86,400,000, the number of milliseconds in a day 1000 x 60 seconds x 60 minutes x 24 hours : Date. Converting Milliseconds to other Intervals As long as you can calculate the number of milliseconds in an interval, you can come up with a number by dividing the total number of milliseconds by the number of milliseconds in the desired interval. What's more, we can apply the modulus % operator to strip out that value to determine the next larger interval. The key is to always go from the smallest interval - milliseconds - to the largest - days: Date. In fact it is loosely based on it. I was planning on recreating it in its complete form for your enjoyment, but, thankfully someone has already beat me to it. That someone is Rob Eberhardt of. It's part of his excellent. It's free to use as long as you give credit where credit is due. His function offers a lot of advantages over the simple one presented above. For starters, his can calculate the month interval, which cannot be done by dividing into the number of milliseconds since month lengths differ. It also supports setting the first day of the week to something other than Sunday. It will feature the new HTML5 Date Input control, as well as a jQuery widget fallback. But first, we will be creating some specialized functions to deal with leap years. About the Author resides in Ottawa, Canada, and is the founder of. Rob has built systems for Intelligence-related organizations such as Canada Border Services, CSIS as well as for numerous commercial businesses. Rob to receive a free estimate on your software project. Should you hire Rob and his firm, you'll receive 15% off for mentioning that you heard about it here!

This example converts the dates to objects as the getTime function won't work unless it's an Date object. This answer is wrong. As for always returning a positive number, that was a feature : Typically when one talks about the number of days between two dates, that number is positive. This can return some results that feel a little weird, but aren't technically incorrect. There are lots of solutions, but they only offer the difference in the format of either days OR months OR years, or they are not correct meaning not taking care of actual number of days in a month or leap years, etc. The subtraction operator - coerces the arguments to number, so the La returns its time value. Kind regards, Pascal Petruch Hello there, thank you for the answer, but it doesen't work for my case. Should you hire Rob and his firm, you'll receive 15% off for mentioning that you heard about it here. However, the millisecond approach would give you 1 for 0 months and 1 day, since the date range includes a leap year. Once both Dates have been converted, subtracting the later one from the earlier one returns the difference in milliseconds. RajeevPNadig's answer was what I was looking for, but the code returns incorrect values as glad.